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36x^2+85x+50=0
a = 36; b = 85; c = +50;
Δ = b2-4ac
Δ = 852-4·36·50
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(85)-5}{2*36}=\frac{-90}{72} =-1+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(85)+5}{2*36}=\frac{-80}{72} =-1+1/9 $
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